Zur Zeit erweitere ich ein TikZ-Trapez (Eingangsfrage mit Code: [Trapezförmige Tabelle][1]); und würde gerne wissen, wie ich \begin{tikzpicture}[every node/.append style={minimum width=1cm, minimum height=1cm}] % Eckpunkte \node (1) at (14,16) {1}; \node (2) at (1,16) {2}; \node (3) at (2,0) {3}; \node (4) at (9,0) {4}; % Gitterpunkte der oberen und unteren Seite: \node (O1) at ($ (1) !.125! (2) $) {O1}; \node (O2) at ($ (1) !.25! (2) $) {O2}; \node (O3) at ($ (1) !.375! (2) $) {O3}; \node (O4) at ($ (1) !.5! (2) $) {O4}; \node (O5) at ($ (1) !.625! (2) $) {O5}; \node (O6) at ($ (1) !.75! (2) $) {O6}; \node (O7) at ($ (1) !.875! (2) $) {O7}; \node (U1) at ($ (4) !.125! (3) $) {U1}; \node (U2) at ($ (4) !.25! (3) $) {U2}; \node (U3) at ($ (4) !.375! (3) $) {U3}; \node (U4) at ($ (4) !.5! (3) $) {U4}; \node (U5) at ($ (4) !.625! (3) $) {U5}; \node (U6) at ($ (4) !.75! (3) $) {U6}; \node (U7) at ($ (4) !.875! (3) $) {U7}; % Gitterpunkte der linken und rechten Seite: \node (L1) at ($ (2) !.1429! (3) $) {L1}; \node (L2) at ($ (2) !.2857! (3) $) {L2}; \node (L3) at ($ (2) !.4286! (3) $) {L3}; \node (L4) at ($ (2) !.5714! (3) $) {L4}; \node (L5) at ($ (2) !.7143! (3) $) {L5}; \node (L6) at ($ (2) !.8571! (3) $) {L6}; \node (R1) at ($ (1) !.1429! (4) $) {R1}; \node (R2) at ($ (1) !.2857! (4) $) {R2}; \node (R3) at ($ (1) !.4286! (4) $) {R3}; \node (R4) at ($ (1) !.5714! (4) $) {R4}; \node (R5) at ($ (1) !.7143! (4) $) {R5}; \node (R6) at ($ (1) !.8571! (4) $) {R6}; % Festlegung senkrechter und waagerechter Reihen: \path [name path=O1--U1] (O1) -- (U1); \path [name path=O2--U2] (O2) -- (U2); \path [name path=O3--U3] (O3) -- (U3); \path [name path=O4--U4] (O4) -- (U4); \path [name path=O5--U5] (O5) -- (U5); \path [name path=O6--U6] (O6) -- (U6); \path [name path=O7--U7] (O7) -- (U7); \path [name path=L1--R1] (L1) -- (R1); \path [name path=L2--R2] (L2) -- (R2); \path [name path=L3--R3] (L3) -- (R3); \path [name path=L4--R4] (L4) -- (R4); \path [name path=L5--R5] (L5) -- (R5); \path [name path=L6--R6] (L6) -- (R6); % Schnittpunkte der senkrechen mit den waagerechten Reihen als neue Gitterpunkte: \path [name intersections = {of=O1--U1 and L1--R1, by=11}]; \node at (11) {11}; \path [name intersections = {of=O2--U2 and L1--R1, by=21}]; \node at (21) {21}; \path [name intersections = {of=O3--U3 and L1--R1, by=31}]; \node at (31) {31}; \path [name intersections = {of=O4--U4 and L1--R1, by=41}]; \node at (41) {41}; \path [name intersections = {of=O5--U5 and L1--R1, by=51}]; \node at (51) {51}; \path [name intersections = {of=O6--U6 and L1--R1, by=61}]; \node at (61) {61}; \path [name intersections = {of=O7--U7 and L1--R1, by=71}]; \node at (71) {71}; \path [name intersections = {of=O1--U1 and L2--R2, by=12}]; \node at (12) {12}; \path [name intersections = {of=O2--U2 and L2--R2, by=22}]; \node at (22) {22}; \path [name intersections = {of=O3--U3 and L2--R2, by=32}]; \node at (32) {32}; \path [name intersections = {of=O4--U4 and L2--R2, by=42}]; \node at (42) {42}; \path [name intersections = {of=O5--U5 and L2--R2, by=52}]; \node at (52) {52}; \path [name intersections = {of=O6--U6 and L2--R2, by=62}]; \node at (62) {62}; \path [name intersections = {of=O7--U7 and L2--R2, by=72}]; \node at (72) {72}; \path [name intersections = {of=O1--U1 and L3--R3, by=13}]; \node at (13) {13}; \path [name intersections = {of=O2--U2 and L3--R3, by=23}]; \node at (23) {23}; \path [name intersections = {of=O3--U3 and L3--R3, by=33}]; \node at (33) {33}; \path [name intersections = {of=O4--U4 and L3--R3, by=43}]; \node at (43) {43}; \path [name intersections = {of=O5--U5 and L3--R3, by=53}]; \node at (53) {53}; \path [name intersections = {of=O6--U6 and L3--R3, by=63}]; \node at (63) {63}; \path [name intersections = {of=O7--U7 and L3--R3, by=73}]; \node at (73) {73}; \path [name intersections = {of=O1--U1 and L4--R4, by=14}]; \node at (14) {14}; \path [name intersections = {of=O2--U2 and L4--R4, by=24}]; \node at (24) {24}; \path [name intersections = {of=O3--U3 and L4--R4, by=34}]; \node at (34) {34}; \path [name intersections = {of=O4--U4 and L4--R4, by=44}]; \node at (44) {44}; \path [name intersections = {of=O5--U5 and L4--R4, by=54}]; \node at (54) {54}; \path [name intersections = {of=O6--U6 and L4--R4, by=64}]; \node at (64) {64}; \path [name intersections = {of=O7--U7 and L4--R4, by=74}]; \node at (74) {74}; \path [name intersections = {of=O1--U1 and L5--R5, by=15}]; \node at (15) {15}; \path [name intersections = {of=O2--U2 and L5--R5, by=25}]; \node at (25) {25}; \path [name intersections = {of=O3--U3 and L5--R5, by=35}]; \node at (35) {35}; \path [name intersections = {of=O4--U4 and L5--R5, by=45}]; \node at (45) {45}; \path [name intersections = {of=O5--U5 and L5--R5, by=55}]; \node at (55) {55}; \path [name intersections = {of=O6--U6 and L5--R5, by=65}]; \node at (65) {65}; \path [name intersections = {of=O7--U7 and L5--R5, by=75}]; \node at (75) {75}; \path [name intersections = {of=O1--U1 and L6--R6, by=16}]; \node at (16) {16}; \path [name intersections = {of=O2--U2 and L6--R6, by=26}]; \node at (26) {26}; \path [name intersections = {of=O3--U3 and L6--R6, by=36}]; \node at (36) {36}; \path [name intersections = {of=O4--U4 and L6--R6, by=46}]; \node at (46) {46}; \path [name intersections = {of=O5--U5 and L6--R6, by=56}]; \node at (56) {56}; \path [name intersections = {of=O6--U6 and L6--R6, by=66}]; \node at (66) {66}; \path [name intersections = {of=O7--U7 and L6--R6, by=76}]; \node at (76) {76}; ... über eine for -Schleife oder soetwas vereinfachen könnte? [1]: http://texwelt.de/wissen/fragen/3610/trapezformige-tabelle-mit-tikz

Zur Zeit erweitere ich ein TikZ-Trapez; TikZ-Trapez (Eingangsfrage mit Code: [Trapezförmige Tabelle][1]); und würde gerne wissen, wie ich \path [name intersections = {of=O1--U1 and L1--R1, by=11}]; \node at (11) {11}; \path [name intersections = {of=O2--U2 and L1--R1, by=21}]; \node at (21) {21}; \path [name intersections = {of=O3--U3 and L1--R1, by=31}]; \node at (31) {31}; \path [name intersections = {of=O4--U4 and L1--R1, by=41}]; \node at (41) {41}; \path [name intersections = {of=O5--U5 and L1--R1, by=51}]; \node at (51) {51}; \path [name intersections = {of=O6--U6 and L1--R1, by=61}]; \node at (61) {61}; \path [name intersections = {of=O1--U1 and L2--R2, by=12}]; \node at (12) {12}; \path [name intersections = {of=O2--U2 and L2--R2, by=22}]; \node at (22) {22}; \path [name intersections = {of=O3--U3 and L2--R2, by=32}]; \node at (32) {32}; \path [name intersections = {of=O4--U4 and L2--R2, by=42}]; \node at (42) {42}; \path [name intersections = {of=O5--U5 and L2--R2, by=52}]; \node at (52) {52}; ... über eine for -Schleife oder soetwas vereinfachen könnte? [1]: http://texwelt.de/wissen/fragen/3610/trapezformige-tabelle-mit-tikz

Zur Zeit erweitere ich ein TikZ-Trapez; und würde gerne wissen, wie ich \path [name intersections = {of=O1--U1 and L1--R1, by=11}]; \node at (11) {11}; \path [name intersections = {of=O2--U2 and L1--R1, by=21}]; \node at (21) {21}; \path [name intersections = {of=O3--U3 and L1--R1, by=31}]; \node at (31) {31}; \path [name intersections = {of=O4--U4 and L1--R1, by=41}]; \node at (41) {41}; \path [name intersections = {of=O5--U5 and L1--R1, by=51}]; \node at (51) {51}; \path [name intersections = {of=O6--U6 and L1--R1, by=61}]; \node at (61) {61}; \path [name intersections = {of=O1--U1 and L2--R2, by=12}]; \node at (12) {12}; \path [name intersections = {of=O2--U2 and L2--R2, by=22}]; \node at (22) {22}; \path [name intersections = {of=O3--U3 and L2--R2, by=32}]; \node at (32) {32}; \path [name intersections = {of=O4--U4 and L2--R2, by=42}]; \node at (42) {42}; \path [name intersections = {of=O5--U5 and L2--R2, by=52}]; \node at (52) {52}; ... über eine for -Schleife oder soetwas vereinfachen könnte?

echt stark, vielen Dank! :-) noch eine andere Frage: zur Zur Zeit erweitere ich das Trapez; ein TikZ-Trapez; und würde gerne wissen, wie ich --- \path [name intersections = {of=O1--U1 and L1--R1, by=11}]; \node at (11) {11}; \path [name intersections = {of=O2--U2 and L1--R1, by=21}]; \node at (21) {21}; \path [name intersections = {of=O3--U3 and L1--R1, by=31}]; \node at (31) {31}; \path [name intersections = {of=O4--U4 and L1--R1, by=41}]; \node at (41) {41}; \path [name intersections = {of=O5--U5 and L1--R1, by=51}]; \node at (51) {51}; \path [name intersections = {of=O6--U6 and L1--R1, by=61}]; \node at (61) {61}; \path [name intersections = {of=O1--U1 and L2--R2, by=12}]; \node at (12) {12}; \path [name intersections = {of=O2--U2 and L2--R2, by=22}]; \node at (22) {22}; \path [name intersections = {of=O3--U3 and L2--R2, by=32}]; \node at (32) {32}; \path [name intersections = {of=O4--U4 and L2--R2, by=42}]; \node at (42) {42}; \path [name intersections = {of=O5--U5 and L2--R2, by=52}]; \node at (52) {52}; ... ------ über eine for -Schleife oder soetwas vereinfachen könnte?

echt stark, vielen Dank! :-) noch eine andere Frage: zur Zeit erweitere ich das Trapez; und würde gerne wissen, wie ich --- \path [name intersections = {of=O1--U1 and L1--R1, by=11}]; \node at (11) {11}; \path [name intersections = {of=O2--U2 and L1--R1, by=21}]; \node at (21) {21}; \path [name intersections = {of=O3--U3 and L1--R1, by=31}]; \node at (31) {31}; \path [name intersections = {of=O4--U4 and L1--R1, by=41}]; \node at (41) {41}; \path [name intersections = {of=O5--U5 and L1--R1, by=51}]; \node at (51) {51}; \path [name intersections = {of=O6--U6 and L1--R1, by=61}]; \node at (61) {61}; \path [name intersections = {of=O1--U1 and L2--R2, by=12}]; \node at (12) {12}; \path [name intersections = {of=O2--U2 and L2--R2, by=22}]; \node at (22) {22}; \path [name intersections = {of=O3--U3 and L2--R2, by=32}]; \node at (32) {32}; \path [name intersections = {of=O4--U4 and L2--R2, by=42}]; \node at (42) {42}; \path [name intersections = {of=O5--U5 and L2--R2, by=52}]; \node at (52) {52}; ... ------ über eine for -Schleife oder soetwas vereinfachen könnte?