Mit tikzmath kann ich 2^n-1 für maximal n = 13 berechnen. Wie kann ich hier größere Werte von n einsetzen? Geht das evtl. mit dem Paket pgfplots?

Öffne in Overleaf
Code, hier editierbar zum Übersetzen:
%\documentclass[]{article}
\documentclass[border=5mm, varwidth]{standalone}
\usepackage[german]{babel}
\usepackage{tikz}
\usetikzlibrary{math}
\begin{document}
\tikzmath{
function mersenne(\N) {return int(2^\N-1);};
}
\foreach \n in {1,...,13}{
\pgfmathparse{mersenne(\n)}\pgfmathresult,
}\\
\tikzmath{
function Mersenne(\N) {return int(2^\N-1);};
int \M, \n;
for \n in {1,...,13}{
\M = Mersenne(\n);
print {\M, };
};
}\\
Maximal n = 13.
\end{document}
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gefragt 08 Jan '18, 16:55

cis's gravatar image

cis
9.6k104462491
Akzeptiert-Rate: 29%


Du kannst die FPU (Floating Point Unit) verwenden. Leider scheint die FPU nicht richtig mit tikzmath zu kooperieren (siehe auch pgfplots on tikzmath function with conditionals returns an error)

Öffne in Overleaf
Code, hier editierbar zum Übersetzen:
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{fpu,math}
\pgfkeys{/pgf/fpu=true}
\begin{document}
\tikzmath{
function mersenne(\N) {return int(2^\N-1);};
}
\foreach \n in {1,...,250}{
\pgfmathparse{mersenne(\n)}
\pgfmathprintnumber\pgfmathresult,
}
\end{document}
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Permanenter link

beantwortet 09 Jan '18, 04:04

Henri's gravatar image

Henri
15.7k143943
Akzeptiert-Rate: 46%

bearbeitet 09 Jan '18, 04:06

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gestellte Frage: 08 Jan '18, 16:55

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zuletzt geändert: 09 Jan '18, 04:06