Vertikale Ausrichtung einer Formel in einer beamer block-Umgebung

Ich würde gerne in folgendem Beispiel die Formel in der Block-Umgebung bündig zum restlichen Text haben, d.h. das x in der Formel soll auf der Höhe des x im Text sein.

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Code, hier editierbar zum Übersetzen:

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\documentclass[12pt]{beamer}
\usepackage[utf8]{inputenc}
\usetheme{AnnArbor}
\newenvironment<>{definitionblock}[2][\textwidth]{%
  \begin{minipage}{#1}
    \setlength{\textwidth}{#1}
    \begin{actionenv}#3%
      \def\insertblocktitle{#2}%
      \par%
      \setbeamercolor{block body}{bg=blue!30}
      \usebeamertemplate{block begin}%
      \par%
      \begin{center}}
     {\end{center}%
      \par%
      \usebeamertemplate{block end}%
    \end{actionenv}%
  \end{minipage}%
}
\begin{document}
\begin{frame}
Text
\begin{definitionblock}[5cm]{}
  $g(x) = a \cdot f(b\cdot(x-c))+d$
\end{definitionblock}%
Text
\end{frame}
\end{document}
 
 
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Ich habe dies bislang mit einer raisebox und einem durch Tests ermittelten Wert von 1.4mm erreicht.

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Code, hier editierbar zum Übersetzen:

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\documentclass[12pt]{beamer}
\usepackage[utf8]{inputenc}
\usetheme{AnnArbor}
\newenvironment<>{definitionblock}[2][\textwidth]{%
  \begin{minipage}{#1}
    \setlength{\textwidth}{#1}
    \begin{actionenv}#3%
      \def\insertblocktitle{#2}%
      \par%
      \setbeamercolor{block body}{bg=blue!30}
      \usebeamertemplate{block begin}%
      \par%
      \begin{center}}
     {\end{center}%
      \par%
      \usebeamertemplate{block end}%
    \end{actionenv}%
  \end{minipage}%
}
\begin{document}
\begin{frame}
Text
\raisebox{1.4mm}{%
  \begin{definitionblock}[5cm]{}
    $g(x) = a \cdot f(b\cdot(x-c))+d$
  \end{definitionblock}%
}
Text
\end{frame}
\end{document}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Gibt es eine Möglichkeit, den Wert für raisebox exakt anzugeben bzw. zu berechnen?

gefragt 23 Feb '16, 16:13

tom75
2.2k●28●79●84
Akzeptiert-Rate: 57%

Eine Antwort:

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Um den exakten Wert für die \raisebox zu ermitteln muss man in die Defintion von block begin und block end hineinschauen. Man findet diese in beamerinnerthemedefault.sty.

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Code, hier editierbar zum Übersetzen:

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\defbeamertemplate*{block begin}{default}
{
  \par\vskip\medskipamount%
  \begin{beamercolorbox}[colsep*=.75ex]{block title}
    \usebeamerfont*{block title}\insertblocktitle%
  \end{beamercolorbox}%
  {\parskip0pt\par}%
  \ifbeamercolorempty[bg]{block title}
  {}
  {\ifbeamercolorempty[bg]{block body}{}{\nointerlineskip\vskip-0.5pt}}%
  \usebeamerfont{block body}%
  \begin{beamercolorbox}[colsep*=.75ex,vmode]{block body}%
    \ifbeamercolorempty[bg]{block body}{\vskip-.25ex}{\vskip-.75ex}\vbox{}%
}
\defbeamertemplate*{block end}{default}  
{\end{beamercolorbox}\vskip\smallskipamount}
 
 
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Wenn man aufmerksam schaut und alle Längen mit den richtigen Vorzeichen zusammenaddiert erhält man

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\dimexpr\medskipamount-\smallskipamount-0.5pt+0.25ex\relax
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Permanenter link

beantwortet 24 Feb '16, 13:31

Henri
15.7k●13●39●43
Akzeptiert-Rate: 46%

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Frage-Themen:

ausrichtung ×70
vertikal ×15
block-umgebung ×3
raisebox ×2

gestellte Frage: 23 Feb '16, 16:13

Frage wurde gesehen: 7,071 Mal

zuletzt geändert: 24 Feb '16, 13:31

Vertikale Ausrichtung einer Formel in einer beamer block-Umgebung

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