Tikz / calc: Strecken vorgegebener Richtung und vorgegebener Länge konstruieren

Die roten Strecken stehen jeweils senkrecht auf einer schwarzen.
(Es kommt richtig raus mit dem rechten Winkel, aber die Syntax ist etwas komisch geraten... vielleicht geht es besser?)

Wie erreiche ich, dass die roten Strecken alle genau die Länge 1 haben?

Öffne in Overleaf

Code, hier editierbar zum Übersetzen:

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\documentclass[border=5pt, tikz]{standalone}
\usepackage{tikz, amsmath}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}[
nodes={fill=red,circle, inner sep=1pt,}
]
\node [label=left:$A$] (A) at (0,0) {};
\node [label=right:$B$] (B) at (1,0) {};
\draw (A) -- (B);
\node [label=above:$C$] (C) at ($(B)!1!-90:(A)$) {};
\draw[red] (B) -- (C);
\draw (A) -- (C);
\node [label=above:$D$] (D) at ($(C)!1!-90:(A)$) {};
\draw[red] (C) -- (D);
\draw (A) -- (D);
\node [label=above:$E$] (E) at ($(D)!1!-90:(A)$) {};
\draw[red] (D) -- (E);
\draw (A) -- (E);
\end{tikzpicture}
\end{document}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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tikz calc

gefragt 07 Nov '18, 21:50

cis
9.6k●103●460●491
Akzeptiert-Rate: 29%

bearbeitet 07 Nov '18, 21:51

Eine Antwort:

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Da die Länge 1 in dem Beispiel 1cm entspricht, könntest Du

Öffne in Overleaf

1
($(C)!1!-90:(A)$)
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Öffne in Overleaf

1
($(C)!1cm!-90:(A)$)
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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ändern. Analog für die anderen Punkte, die mit der gleichen Syntax konstruiert wurden.

Alternativ kannst Du die Option turn für eine relative Drehung zum Pfad verwenden. Das geht dann auch ohne die Bibliothek calc:

Öffne in Overleaf

Code, hier editierbar zum Übersetzen:

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\documentclass[border=5pt, tikz]{standalone}
\begin{document}
\begin{tikzpicture}
\path [nodes={fill=red,circle, inner sep=1pt}]
  (0,0) node [label=left:$A$] (A) {}
  (1,0) node [label=right:$B$] (B) {}
  +(90:1) node [label=above:$C$] (C) {}
%
  (A) -- (C)
      -- ([turn]90:1) node [label=above:$D$] (D) {}
  (A) -- (D)
      -- ([turn]90:1) node [label=above:$E$] (E) {} 
;
\draw (A) foreach \p in {B,C,D,E} {edge (\p)};
\draw[red] (B) -- (C) -- (D) -- (E);
\end{tikzpicture}
\end{document}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Ergebnis in beiden Fällen:

Permanenter link

beantwortet 07 Nov '18, 23:22

esdd
17.8k●30●42●57
Akzeptiert-Rate: 62%

bearbeitet 07 Nov '18, 23:31

Aja, sehr gut. Das !1cm! hat mir gerade gefehlt.

(08 Nov '18, 00:25) cis

Mit \usetikzlibrary{intersections} kann ich es lösen:

Öffne in Overleaf

Code, hier editierbar zum Übersetzen:

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\documentclass[border=5pt, tikz]{standalone}
\usepackage{tikz, amsmath}
\usetikzlibrary{calc}
\usetikzlibrary{intersections}
\begin{document}
\begin{tikzpicture}[
nodes={fill=red,circle, inner sep=1pt,},
Hilfe/.style={
gray, draw,
nodes={fill=gray,circle, inner sep=1pt,},
}
]
\node [label=left:$A$] (A) at (0,0) {};
\node [label=right:$B$] (B) at (1,0) {};
\draw (A) -- (B);
%\draw (B) circle[radius=1];
\node [label=above:$C$] (C) at ($(B)!1!-90:(A)$) {};
\draw[red] (B) -- (C);
\draw (A) -- (C);
\node [Hilfe, label=above:$Dr$] (Dr) at ($(C)!1!-90:(A)$) {};
\path[Hilfe, name path=Strecke] (C) -- (Dr);
\path[Hilfe, name path=Kreis] (C) circle[radius=1];
\draw [red, name intersections={of=Strecke and Kreis}]
(C) -- (intersection-1) coordinate (D);
\draw (A) -- (D) node[label=$D$]{}; % Radius
\node [Hilfe, label=above:$Er$] (Er) at ($(D)!1!-90:(A)$) {};
\draw[name path=Strecke] (D) -- (Er);
\draw[Hilfe, name path=Kreis] (D) circle[radius=1];
\draw [red, name intersections={of=Strecke and Kreis}]
(D) -- (intersection-1) coordinate (E);
\draw (A) -- (E) node[label=$E$]{}; % Radius
\node [Hilfe, label=above:$Fr$] (Fr) at ($(E)!1!-90:(A)$) {};
\draw[name path=Strecke] (E) -- (Fr);
\draw[Hilfe, name path=Kreis] (E) circle[radius=1];
\draw [red, name intersections={of=Strecke and Kreis}]
(E) -- (intersection-1) coordinate (F);
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Permanenter link

beantwortet 07 Nov '18, 23:29

cis
9.6k●103●460●491
Akzeptiert-Rate: 29%

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gestellte Frage: 07 Nov '18, 21:50

Frage wurde gesehen: 6,726 Mal

zuletzt geändert: 08 Nov '18, 00:25

Tikz / calc: Strecken vorgegebener Richtung und vorgegebener Länge konstruieren

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